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(4/x^2+3x-10)-(1/x^2+x-6)=3/x^2-x-12
We move all terms to the left:
(4/x^2+3x-10)-(1/x^2+x-6)-(3/x^2-x-12)=0
Domain of the equation: x^2+3x-10)!=0
x∈R
Domain of the equation: x^2+x-6)!=0
x∈R
Domain of the equation: x^2-x-12)!=0We get rid of parentheses
x∈R
4/x^2+3x-1/x^2-x-3/x^2+x-10+6+12=0
We multiply all the terms by the denominator
3x*x^2-x*x^2+x*x^2-10*x^2+6*x^2+12*x^2+4-1-3=0
We add all the numbers together, and all the variables
8x^2+3x*x^2-x*x^2+x*x^2=0
Wy multiply elements
8x^2+3x^3-1x^3+x^3=0
We do not support expression: x^3
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